John Porter writes: > I didn't realize until today that method names are only looked up > in the objects's inheritance tree if unqualified. If qualified > (and it goes without saying that Fully Qualified is the only kind), > the fully named sub is called, regardless of the class of the object. > Somewhat unexpected -- though not unpleasant. Almost true. If you say: Foo::moo($obj) then you're specifying exactly which subroutine (ahem, method) should be called. If you say: $obj->Foo:moo() then you're starting the method search in Foo::, looking for the method moo(). Inheritance applies with the -> but not with the mundane sub call. If you're doing this to call an overridden method, you probably want $obj->SUPER::moo() Nat ==== Want to unsubscribe from Fun With Perl? Well, if you insist... ==== Send email to <fwp-request@technofile.org> with message _body_ ==== unsubscribe