On Mon, May 01, 2000 at 04:17:07PM -0400, Bernie Cosell wrote: > > a & (a-1) turns off the lowest-order bit in a (binary) number. Can you > find some reasonable way to turn off the *highest* order bit in the > number? Best I could find was to do the a&(a-1) in a loop and just > remember the last-nonzero-value... but it'd sure be neat if there was a > trick to find that bit directly without the loop... How about this? sub high_off { my $n = shift; $n -= 2 ** int(log($n) / log(2)); } Ronald ==== Want to unsubscribe from Fun With Perl? Well, if you insist... ==== Send email to <fwp-request@technofile.org> with message _body_ ==== unsubscribe