On Sun, 25 Jun 2000 20:15:21 PDT, "Perl lover" wrote: :But if you read the C program.. the precision is the whole point :here. I tried to play with Math::BigFloat.. seems can't :come up with something easy.. How about this: use Math::BigFloat; my $p = new Math::BigFloat "0"; for(0..280){ my $i=$_*8; $p += (16**-$_)*(4/($i+1)-2/($i+4)-1/($i+5)-1/($i+6)); } print $p; Michael ==== Want to unsubscribe from Fun With Perl? Well, if you insist... ==== Send email to <fwp-request@technofile.org> with message _body_ ==== unsubscribe