alex avriette wrote: > Curiously, I get a different number. But no matter what I assign it I get > that same number. So I dont think it is "converting" the number to a > scalar per se. No, it's converting a scalar (any scalar) to a number, just as Sean said. In these tests, it's numericizing a ref, via the same mechanism that allows refs to be compared using == (I suppose). So the value of the number depends on the value of the ref. $= = \$x; print "$=\n"; $= = \$y; print "$=\n"; $= = \$a; print "$=\n"; $= = \$b; print "$=\n"; 135104960 135119868 135120012 135120072 -- John Porter Like music? Then you're gonna love this. I was into these dudes before anybody. Asked me to be the manager. ==== Want to unsubscribe from Fun With Perl? Well, if you insist... ==== Send email to <fwp-request@technofile.org> with message _body_ ==== unsubscribe