> At 17:23 -0700 07/27/1999, Vicki Brown wrote: >> foo() is unambiguously a >> function call. So is &foo. foo is not. >> &foo() would be redundant. Isn't &foo() a prototyping issue? And no, it's not a CGI question, so ... ??? -Sneex- :] ==== Want to unsubscribe from this list? ==== Send mail with body "unsubscribe" to macperl-webcgi-request@macperl.org