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Re: [MacPerl] Bit-wise logical operators in MacPerl
Q: (To paraphrase...) Why does /foo | bar/ match any line with foo or bar,
and not a line with the bitwise OR of 'foo ' and ' bar'?
A: Because in a regular expression, | separates two distinct options.
| in a regex says that the regex matches if the stuff on the left
or right matches. I don't even know how you *do* a bitwise OR
in perl... But I expect it's documented.
Peter