At 10:51 96-04-26, kevin mason wrote: >is it possible to get the "regular" filenames from @ARGV instead of the >full pathnames... if not, i guess i'll have to massage an >@ARGV copy with substitution? Not directly, as you'd not be able to open the files, then! If you *really* want to do that, here's a hack: grep( s/^.*://, @ARGV ); Although I don't know why you'd want this. If what you mean is that you'd like the base name of a given full path, use a function like: sub basename { local( $path, $base ) = $_[0] =~ /^(.*:)?(.*)$/; wantarray ? ( $path, $base ) : $base; } on each individual file name. This will let you do things like: while( <> ) { print "Reading from file " . &basename( $ARGV ), "\n" if $. == 1; # your code here close( ARGV ) if eof( ARGV ); # reset line numbers } --Hal Hal Wine <hal@dtor.com> voice: 510/482-0597