[MacPerl] In the continuing vein of substitution....

["Mark Manning/Muniz Eng." <markem@flash.net>]

Try this:

#!/usr/local/bin/perl

    @a = <<END_NUMBERS;
0
1
2
3
4
5
6
7
8
9
10
END_NUMBERS

    print "Yes\n" if @a =~ /10/;
    print "No\n" if @a !~ /10/;

    undef @a;

    for( $i=0; $i<=10; $i++ ){
        $a[$i] = $i + 1;
        }

    print "Yes\n" if @a =~ /10/;
    print "No\n" if @a !~ /10/;
    exit( 0 );

The answers are "No" and "No";  However, Chris' example of:

	@a = 0..9;
	print "Yes\n" if @a =~ /10/;

Returns "Yes".  Go figure.  :-)

My input on the above is that the first example converts the numbers to
letters.  The second example though clearly does arithmetic (adding one
to the number) and therefore should be saved as a number (ie: 1-11).  So
it should be stored like Chris' example and should return "Yes" anyway. 
But it doesn't.  :-)

(Hey!  Is this counted as testing?  ;-) )

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