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Re: [MacPerl] ?:



On Thu, 30 Dec 1999 13:56:51 -0500, Ronald J Kimball wrote:

>       Because this operator produces an assignable result, using
>       assignments without parentheses will get you in trouble.

And when we add to that the fact that an assignment is an lvalue too,
the puzzle is complete.

	($b = 1) = 2;
	print $b;
-->
	2

-- 
	Bart.

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