Re: [MacPerl] Directory Size

[akira@discover-net.net (Akira)]

At 2:29 PM 6/25/97, Chris Nandor wrote:

>At 10.44 6/25/97, Strider wrote:
>
>(snip)
>>How does one find the size of a directory? I can't seem to find the
>>function/command for it, and I'm really at a loss.
>
>I don't think there is a neat way to find the latter; I think you would
>have to iterate through the directory structure and go file by file.  As to
>the former:
>
>#!perl
>$dir="PowerPudgeII:";
>opendir(D,$dir) || die $!;
>while(readdir(D)){$x++}
>close(D);
>print $x;
>__END__


The file operator '-s' returns the number of files if tested against a
directory, and the size in bytes if tested against a file.

So, the following will check both the number of files in a given directory,
plus the "size" of the directory in bytes:

__BEGIN__
#!/usr/bin/perl

$dir = "HD:some:directory";       # On UNIX, should be '/HD/some/directory'
$total = 0;                       # Just initializing

$size = (-s $dir);                # Get the number of files in the dir
print "Number of files in $dir: $size\n";

opendir (READ, $dir) || die;      # Now open the directory
while ($file = readdir(READ)) {   # Get each file name
    $total += (-s "$dir:$file");  # Get the size and add. Note the delimiter
}

print "Total size of the $dir: $total bytes\n";
exit;
__END__

Hope this helps.

--Akira

~~~~~~~~~~~~~~~~~~~~~~~~~  AKIRA HANGAI ~~~~~~~~~~~~~~~~~~~~~~~~~
 Network Connectivity Specialist            Advanced Vet Systems
 akira@discover-net.net                Phone: (715)834-0355 x220
 http://www.advancedvet.com                   Fax: (715)834-0165
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~



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