=Ronald wrote: > On Sat, Feb 12, 2000 at 03:33:54PM +0100, Detlef Lindenthal wrote: > > $IPN =~ s/\./x/g; > > @IPN = split "x", $IPN; > > ## Sorry for these two lines -- but how could I have split at "."?? > > ## This does not work: @IPN = split ".", $1; > > ## nor does this: @IPN = split "\.", $1; > The same way you change the periods to Xs. The first argument to split is > a _regular expression_. > @IPN = split "\\.", $1; # workable > @IPN = split "\.", $1; # also workable > @IPN = split /\./, $1; # PREFERRED > @IPN = split "\.", $1; > Ronald Hi Ronald, thank you for repairing. But I do not agree completely: =cut $_ = "asdf.asdf.asdf.asdf"; s;a;aa;g; ## here even ; is allowed. print "\n(1.) ", join " / ", split "\." , $_; ## not workable on my machine!! print "\n(2.) ", join " / ", split '\.', $_; ## works fine print "\n(3.) ", join " / ", split "\\.", $_; ## works fine -- why?? print "\n(4.) ", join ' / ', split /\./, $_; ## works fine print "\n(5.) ", join " / ", split /\\./, $_; ## does not split #print"\n(6.) ", join " / ", split |\.|, $_; ## would yield a syntax error =You write: > The first argument to split is a _regular expression_. If so -- why can RE in this case be delimited by " , whereas in other cases " is not allowed? Are there different classes of RE or classes of use of RE? -- If this topic is tooo special, then forget my question. I am glad that my script works :-) Detlef Lindenthal <detlef@lindenthal.com> # ===== Want to unsubscribe from this list? # ===== Send mail with body "unsubscribe" to macperl-request@macperl.org