On Tue, May 29, 2001 at 05:48:00AM +0100, Pense, Joachim wrote: > Daniel S.Wilkerson wrote: > >Therefore, R1 and S have the same cardinality. By the > Schroeder-Cantor-Bernstein > >theorem > >(http://www.math.lsa.umich.edu/~mathsch/courses/Infinity/Cardinality/Lesson > 4.shtml), > >there is a 1-1 onto map between R1 and S. (Perhaps I could be accused of > > The objective of the sub-discussion is not the existence of an 1-1 mapping > between the two sets, but the presentation of an "obvious" one. People have different ideas of obvious :-) But his point is that the "obvious" "almost mapping" really is good enough, in the sense that the corner cases are negligible--which, to a mathematician, is obvious. Really--this mapping would be immediately accepted by any mathematician who wasn't being intentionally pedantic. Andrew ==== Want to unsubscribe from Fun With Perl? Well, if you insist... ==== Send email to <fwp-request@technofile.org> with message _body_ ==== unsubscribe