"Pense, Joachim" wrote: > Daniel S.Wilkerson wrote: > >Bernie Cosell wrote: > > > >> > .. And since there is an obvious, > >> > 1-to-1 mapping between the set of reals between 0 and 1 and the set of > ... > >Therefore, R1 and S have the same cardinality. By the > Schroeder-Cantor-Bernstein > >theorem > >(http://www.math.lsa.umich.edu/~mathsch/courses/Infinity/Cardinality/Lesson > 4.shtml), > >there is a 1-1 onto map between R1 and S. (Perhaps I could be accused of > > The objective of the sub-discussion is not the existence of an 1-1 mapping > between the two sets, but the presentation of an "obvious" one. > > Joachim 1 - That's what *you* think the subject is. It wasn't at all clear that people were clear that there existed such a mapping at all. 2 - Constructing such a mapping in a reasonably straightforward way is not difficult, however it is a bit tedious. Its your opinion whether such a thing is obvious. 3 - The original discussion was about the cardinality of the set of infinte sequences of characters from a finite alphabet. Cantor's Diagonalization Argument shows that this cardinality is strictly greater than countable. This is much more straightforward than any arguments about the Real numbers. Daniel ==== Want to unsubscribe from Fun With Perl? Well, if you insist... ==== Send email to <fwp-request@technofile.org> with message _body_ ==== unsubscribe